c++ - Return error while trying to compile fftw -

it newbie in c++ question. trying apply fft complex 1d data using fftw.

 # include <stdlib.h>  # include <stdio.h>  # include <time.h>  #include  <fftw3.h>   int main(void)  {  int i;  int n=100;  fftw_complex *in;  fftw_complex *out;   fftw_plan plan_forward;  unsigned int seed = 123456789;   in= (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*n);  out= (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*n);  srand ( seed );     ( = 0; < n; i++ )    {    in[i][0] = rand ( );    in[i][1] = rand ( );    }     plan_forward = fftw_plan_dft_1d ( n, in, out, fftw_forward,   fftw_estimate );     fftw_execute ( plan_forward );      ( = 0; < n; i++ )    {      printf ( "  %3d  %12f  %12f\n", i, out[i][0], out[i][1] );    }         fftw_destroy_plan ( plan_forward );         fftw_free ( in );          fftw_free ( out );          return;    } 

after compiling getting error:

error: return-statement no value, in function returning ‘int’ [-fpermissive] return;

i have no idea how fix error. appreciated. thanks.

it should be

int n=100; 

(note ; in place of ,)

and ffftw_malloc should fftw_malloc (one f removed @ beginning).

also, compiler should give line numbers errors, i'd suggest going lines , examining them closely, can learn debugging ;)

finally, main returns int, return statement needs value. (0 should fine.) note: main function special in has implicit return 0; @ end, function return value allowed "fall off end". if use return statement in main have provide value.