php - Mysql insert in two tables where the first table has foreign key and update the first table -
this have in db if insert in bmw car brands example.how update id_make whith id bmw sql.(i know huge mess in code , no aligment)
http://i.stack.imgur.com/gqqg1.png
this form:
<div class="modal-content"> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal">×</button> <h4 class="modal-title">add car:</h4> </div> <div class="modal-body "> <form action="index.php?page=carlist" method="post" autocomplete="off"> <div class="form-group"> <label for="marca">marca:</label> <!-- <input type="text" class="form-control" name="marca" placeholder="marca" data-toggle="modal" data-target="#marca"> --> <div class="input-group"> <div class="input-group-btn"> <input type="text" class="form-control dropdown-toggle " data-toggle="dropdown" placeholder=" <?php if (!isset($brd['name'])) { echo "brand"; } else echo $brd['name']; ?>" name="marca" readonly="readonly"> <ul class="dropdown-menu scrollable"> <?php foreach ($brds $brd) { ?> <li><a href='#'><?php echo $brd['name']; ?></a></li> <?php } ?> </ul> </div> <!-- /btn-group --> </div> <!-- /input-group --> </div> <div class="form-group"> <label for="model">model:</label> <input type="text" class="form-control" name="model" placeholder="model"> </div> <div class="form-group"> <label for="color">color:</label> <input type="test" class="form-control" name="color" placeholder="color"> </div> <div class="form-group"> <label for="release_date">release date:</label> <div class=" date"> <input type="date" class="form-control" name="release_date" placeholder="release date" id='release_date'> <!-- <span class="input-group-addon add-on"><span class="glyphicon glyphicon-calendar"></span></span> --> </div> </div> <div class="form-group"> <label for="value">value:</label> <input type="test" class="form-control" name="value" placeholder="value"> </div> <div class="modal-footer"> <button type="button" class="btn btn-default" data-dismiss="modal">close</button> <input type="submit" name="addcar" class="btn btn-primary" value="add car"> </div> </form> </div> </div>
(the php input on brand show brands db )
when select brand list , put model ,color, value ,release date press add car php makes connection on db insert on table models model of car , need add id brands witch car selected on list , update models id_make id of car.
perhaps need request id of make inserted using:
mysql_insert_id();
id of record inserted, , use id make in other table.
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