plsql - Oracle cusor return result and get value by dynamic column name -


as tittle, want value column name paramater in cursor result.

i not find answer after searching long time,could give help?

--common usage begin     rowvalue in (select code, name tablea)     loop      -- rowvalue.code  rowvalue.name     end loop; end   begin     rowvalue in (select * tablea)     loop         -- tableb keep column's names talbea         columnnames in (select name tableb)         loop          -- want use like:  rowvalue.(columnnames.name)         end loop;     end loop; end 

you can use dbms_sql, this:

declare   l_cursor                integer;   l_column_count          integer;   l_column_descriptions   sys.dbms_sql.desc_tab;   l_column_value          varchar2 (4000);   l_status                integer;    type col_map_tab_type table of integer     index varchar2 (30);    col_map_tab             col_map_tab_type; begin   l_cursor   := sys.dbms_sql.open_cursor;    -- parse sql   sys.dbms_sql.parse (c => l_cursor, statement => 'select * dba_objects rownum <= 10', language_flag => sys.dbms_sql.native);    -- describe columns   sys.dbms_sql.describe_columns (c => l_cursor, col_cnt => l_column_count, desc_t => l_column_descriptions);    in 1 .. l_column_count loop     col_map_tab (l_column_descriptions (i).col_name)   := i;     dbms_sql.define_column (l_cursor,                             i,                             l_column_value,                             4000);   end loop;    l_status   := sys.dbms_sql.execute (l_cursor);    while (sys.dbms_sql.fetch_rows (l_cursor) > 0) loop     column_names in (select column_name                            dba_tab_columns                           table_name = 'dba_objects'                          ,    column_name 'o%') loop       dbms_sql.column_value (l_cursor, col_map_tab (column_names.column_name), l_column_value);       dbms_output.put_line (column_names.column_name || ' = ' || l_column_value);     end loop;   end loop;    sys.dbms_sql.close_cursor (l_cursor); end; 

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