c++ - Producing JSON from C#: WebMessageBodyStyle.Wrapped or WebMessageBodyStyle.Bare? -

i trying write c++ application, using c++ rest sdk lib, process json data produced c# application. c# program can produce json in "wrapped" or "bare" style.

using bodystyle = webmessagebodystyle.wrapped, c# produces json following:

{"echo":"{\"firstname\":\"an'",\"number\":21,\"secondname\":\"pn\"}"} 

using bodystyle = webmessagebodystyle.bare, c# produces json this:

"{\"firstname\":\"an'",\"number\":21,\"secondname\":\"pn\"}" 

how can program recognize type produced: wrapped or bare?

json standard format representing, , exchanging, data. not define terms wrapped or bare. not familiar c# , libraries encoding data json, can make guess based on samples provided.

if have control on c# application, code use bare only. see no advantage, in general, wrapped style. perhaps designed other c# client libraries.

the difference see in produced output structure of data. there no way absolutely certain, 2 samples can @ deserialized object , check if has attribute echo. if does, use value of attribute , if doesn't use object as-is.

since haven't worked in c++ in on decade , not know json library using, give example in javascript (though using style may closer c++). here how 2 objects handled:

var data = json.parse(...); // '...' represents ever text if (data["echo"] !== undefined)     { data = data["echo"]; } console.log("the first name is:", data["firstname"]); 

here psuedo-code example valid java may more recognized , translated c++:

map<string, object> data = json.parse(...); // '...' represents ever text if (data.containskey("echo"))     { data = (map)data.get("echo"); } system.out.println("the first name is: " + data.get("firstname"));