vba - Excel macro to open a folder of excel workbooks and copy 1 cell -

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i have folder of .xlsx files, each identical in layout.

i need write macro in excel open each file in turn (100+ files) data (a name) single cell, , drop in new excel worksheet, move on next , insert below last 1 etc.

giving me list of names data not file names)

here (pretty much) you're trying do. next time little bit of googling before ask! :)

http://www.excel-easy.com/vba/examples/files-in-a-directory.html

rough code unsure if work: here basic idea of need modify in example sent you. if @ example again, need , some. since weren't interested in worksheets, don't have loop through worksheets in workbook. can open up, read cell of interest, , close it. while loop every excel file in directory. again! please modify example accordingly before use it. 

dim directory string, filename string, sheet worksheet, integer, j integer  application.screenupdating = false  directory = "c:\test\" filename = dir(directory & "*.xl??")  while filename <> ""      = + 1     workbooks.open (directory & filename)     workbooks("files-in-a-directory.xls").worksheets(1).cells(i, 1).value = workbooks(filename).worksheets(1).cells(x, y) <-- whatever cell of interest     workbooks(filename).close     filename = dir()  loop  application.screenupdating = true

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