java - How to find the most common character in a String -

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i have quick question. how find common character in string in java. know logically how it, not sure if syntax in correct: 

public class helloworld {   public static void main(string[] args){       string votes = "abbab";      char[] storingarray = votes.tochararray();      int numofb = 0;     int numofa = 0;      if (storingarray.contains("a")) {       numofa++;     } else if (storingarray.contains("b")) {               numofab++;               }      if (numofa = numofb) {     system.out.println("tie");     } else if (numofa > b) {     system.out.println("a");     } else {     system.out.println("b");     }    } }

could me how correctly in java?

you can not compare char array string, below logic should work , give need:

   public static void main(string[] args){          string votes = "abbab";          char[] storingarray = votes.tochararray();          int numofb = 0;         int numofa = 0;         for(char c : storingarray) {             if(c == 'a') {                 numofa++;             }             if(c == 'b') {                 numofb++;             }         }         if (numofa == numofb) {             system.out.println("tie");         } else if (numofa > numofb) {             system.out.println("a");         } else {             system.out.println("b");         }      }

there couple of mistakes in code:

  1. you can not use if (numofa = numofb) not valid expression. should use == compare
  2. you can not compare char array contains method. should used on string object

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