Access multidimensional list value by tuple of indices in python -

i have complex multidimensional utterable object (say, list). want write function access value of element represented tuple of indices. number of dimensions variable. should return none if element not exist:

l = [[[1, 2],       [3, 4]],      [[5, 6],       [7, 8]]] access(l, (0, 0, 0)) # prints 1 access(l, (0, 1, 1)) # prints 4 access(l, (1, 1)) # prints [7, 8] access(l, (0, 1, 2)) # prints none access(l, (0, 0, 0, 0)) # prints none 

how achieve this?

you can using reduce():

def access(obj, indexes):     return reduce(lambda subobj, index: subobj[index] if isinstance(subobj, list) , index < len(subobj) else none, indexes, obj) 

or pointed @chepner, can use def make more readable:

def access(obj, indexes):     def _get_item(subobj, index):          if isinstance(subobj, list) , index < len(subobj):             return subobj[index]         return none      return reduce(_get_item, indexes, obj)