python - Print list while excluding specific named values -

i looking basic way exclude printing item list (not remove/delete) if named value = specified, e.g. = 0

i thought basic this, error not defined.

a = 2 b = 0 c = 4 d = 0 e = 6  lis = [a,b,c,d,e]  while != 0 in range(lis):   print (lis[i])

wanted result:
2
4
6

seems missing simple? or not simple imagined?

python syntax doesn't support conditional you're trying apply it. there several alternatives, though:

you put condition inside loop:

for item in lis:     if item != 0:         print item

you filter list:

for item in filter(lambda i: i!=0, lis):  # filter(none, lis) works     print item

or using list comprehension (technically generator expression here):

for item in (i in lis if != 0):     print item

or skip loop entirely:

print '\n'.join(str(i) in lis if != 0)

YU